Chemical Engineering Thermodynamics Co-efficient of performance for a reversed Carnot cycle working between temperatures T₁ and T₂ (T₁ > T₂) is (T₁ - T₂)/T₂ T₂/(T₁ - T₂) T₁/(T₁ - T₂) (T₁ - T₂)/T₁ (T₁ - T₂)/T₂ T₂/(T₁ - T₂) T₁/(T₁ - T₂) (T₁ - T₂)/T₁ ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics In a working refrigerator, the value of COP is always < 0 > 1 < 1 < 0 > 1 < 1 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics First law of thermodynamics is mathematically stated as dW = dQ + dE dQ = dE + dW dQ = dE - dW dE = dQ + dW dW = dQ + dE dQ = dE + dW dQ = dE - dW dE = dQ + dW ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics For an ideal solution, the value of activity co-efficient is 1 > 1 < 1 1 > 1 < 1 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics 1st law of thermodynamics is nothing but the law of conservation of Momentum Mass None of these Energy Momentum Mass None of these Energy ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x₁. x₂, where A is a constant. The corresponding equation for ln y₁, where y₁ is the activity co-efficient of component 1, is A . x₂² Ax₂ Ax₁ Ax₁² A . x₂² Ax₂ Ax₁ Ax₁² ANSWER DOWNLOAD EXAMIANS APP