Chemical Engineering Thermodynamics Co-efficient of performance for a reversed Carnot cycle working between temperatures T₁ and T₂ (T₁ > T₂) is T₁/(T₁ - T₂) (T₁ - T₂)/T₂ (T₁ - T₂)/T₁ T₂/(T₁ - T₂) T₁/(T₁ - T₂) (T₁ - T₂)/T₂ (T₁ - T₂)/T₁ T₂/(T₁ - T₂) ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Which one is true for a throttling process? The inversion temperature is same for all gases The inversion temperature is different for different gases A gas may have more than one inversion temperatures The inversion temperature is the temperature at which Joule-Thomson co-efficient is infinity The inversion temperature is same for all gases The inversion temperature is different for different gases A gas may have more than one inversion temperatures The inversion temperature is the temperature at which Joule-Thomson co-efficient is infinity ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics What happens in a reversible adiabatic compression? Cooling occurs Pressure is constant Heating occurs Temperature is constant Cooling occurs Pressure is constant Heating occurs Temperature is constant ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Generation of heat by friction is an example of a/an __________ change. Reversible Adiabatic Irreversible Isothermal Reversible Adiabatic Irreversible Isothermal ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A solute distributes itself between two non-miscible solvents in contact with each other in such a way that, at a constant temperature, the ratio of its concentrations in two layers is constant, irrespective of its total amount". This is Followed from Margule's equation A corollary of Henry's law None of these The distribution law Followed from Margule's equation A corollary of Henry's law None of these The distribution law ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is (∂V/∂S)P = (∂T/∂P)S (∂S/∂P)T = -(∂V/∂T)P (∂S/∂V)T = (∂P/∂T)V (∂T/∂V)S = -(∂P/∂S)V (∂V/∂S)P = (∂T/∂P)S (∂S/∂P)T = -(∂V/∂T)P (∂S/∂V)T = (∂P/∂T)V (∂T/∂V)S = -(∂P/∂S)V ANSWER DOWNLOAD EXAMIANS APP