Machine Design Basic shaft is one Whose lower deviation is zero Whose lower as well as upper deviations are zero Whose upper deviation is zero Does not exist Whose lower deviation is zero Whose lower as well as upper deviations are zero Whose upper deviation is zero Does not exist ANSWER DOWNLOAD EXAMIANS APP
Machine Design Taper usually provided on cotter is 1 in 40 1 in 10 1 in 24 1 in 5 1 in 40 1 in 10 1 in 24 1 in 5 ANSWER DOWNLOAD EXAMIANS APP
Machine Design A screw will be self locking, if Efficiency of screw is 100% Friction angle is more than helix angle Friction angle is equal to helix angle Friction angle is less than helix angle Efficiency of screw is 100% Friction angle is more than helix angle Friction angle is equal to helix angle Friction angle is less than helix angle ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length) 3 × (π/4) d² × τ × n 1.875 × (π/4) d² × τ × n 2 × (π/4) d² × τ × n (π/4) d² × τ × n 3 × (π/4) d² × τ × n 1.875 × (π/4) d² × τ × n 2 × (π/4) d² × τ × n (π/4) d² × τ × n ANSWER DOWNLOAD EXAMIANS APP
Machine Design The bearings of heavy series have capacity __________ over the medium series. 40 to 50% 20 to 30% 10 to 20% 30 to 40% 40 to 50% 20 to 30% 10 to 20% 30 to 40% ANSWER DOWNLOAD EXAMIANS APP
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