Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Depth of the section Depth of the neutral axis Maximum tensile stress at the section Maximum compressive stress at the section Depth of the section Depth of the neutral axis Maximum tensile stress at the section Maximum compressive stress at the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures P = 4π² EI/L² is the equation of Euler's crippling load if One end is fixed and other end is free Both the ends are fixed Both the ends are hinged One end is fixed and other end is hinged One end is fixed and other end is free Both the ends are fixed Both the ends are hinged One end is fixed and other end is hinged ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is 0.407 0.307 0.207 0.508 0.407 0.307 0.207 0.508 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 5 m × 50 mm is loaded with 250,000 N. If the modulus of elasticity of the material is 0.2 MN/mm² and Poisson’s ratio is 0.25, the change in the volume of the bar is: 3.125 cm³ 4.125 cm² 1.125 cm³ 2.125 cm³ 3.125 cm³ 4.125 cm² 1.125 cm³ 2.125 cm³ ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A two hinged parabolic arch of span l and rise h carries a load varying from zero at the left end to ? per unit run at the right end. The horizontal thrust is ωl²/16h ωl²/12h ωl²/8h ωl²/4h ωl²/16h ωl²/12h ωl²/8h ωl²/4h ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For beams of uniform strength, if depth is constant, Width b 1/M Width b M Width b M 2 Width b 3 M Width b 1/M Width b M Width b M 2 Width b 3 M ANSWER DOWNLOAD EXAMIANS APP
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