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AREA PROBLEMS

Area Problems
Floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50 cm. The smallest number of tiles needed is?

500
400
300
200

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square room = (10)2 = 100 sq m= 100 x (100)2 sq cm= 100 x 100 x 100 sq cmNow, area of tiles = (50)2 = 50 x 50 sq cm? Number of tiles needed = (Area of square room) / (Area of tile)= (100 x 100 x 100) / (50 x 50) = 400Hence, 400 tiles will be needed.

Area Problems
The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively.

8 cm and 9 cm
6 cm and 10 cm
14 cm and 6 cm
10 cm and 8 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the third side be x.According to the question,x + 20 = 26? x = 26 - 20 = 6 cm ? Each equal side = 20/2 = 10 cm

Area Problems
The ratio of length and breadth of a rectangle is 5 : 3 .If length is 8 m more than breadth, find the area of the rectangle.

240 sq m
185 sq m
250 sq m
300 sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length of rectangle = 5kand breadth of rectangle = 3kAccording to the quecation,5k - 3k = 8 ? 2k =8? k = 4? Lenght = 5k = 5 x 4 = 20 mBreadth = 3k = 3 x 4 = 12 m? Required area = Lenght x Breadth = 20 x 12 = 240 sq m

Area Problems
The ratio between the lenght and the breadth of a rectangle is 2 : 1. If breadth is 5 cm less than the length, what will be the parimeter of the rectangle?

35 cm
25 cm
40 cm
30 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = 2x and breadth = xAccording to the question, 2x - x = 5 ? x = 5? Required perimeter = 2(2x + x) = 6x= 30 cm

Area Problems
The perimeter of a rectangle having area equal to 144 cm 2 and sides in the ratio 4 : 9 is

64 cm
60 cm
56 cm
52 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let l = 4k and b = 9kArea of rectangle = l x b144 = 4k x 9k ? k2 = 144/36 ? k2 = 4? k = 2? l = 8 cm and b = 18 cmPerimeter of rectangle = 2(l + b)= 2(8 + 18)= 2 x 26= 52 cm

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