Engineering Mechanics Angle of friction is the Angle between normal reaction and the resultant of normal reaction and the limiting friction The ratio of minimum friction force to friction force acting when the body is in motion The ratio of minimum friction force to the friction force acting when the body is just about to move Ratio of limiting friction and normal reaction Angle between normal reaction and the resultant of normal reaction and the limiting friction The ratio of minimum friction force to friction force acting when the body is in motion The ratio of minimum friction force to the friction force acting when the body is just about to move Ratio of limiting friction and normal reaction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces, which meet at one point and their lines of action also lie on the same plane, are known as Coplanar non-concurrent forces Non-coplanar non-concurrent forces Coplanar concurrent forces Non-coplanar concurrent forces Coplanar non-concurrent forces Non-coplanar non-concurrent forces Coplanar concurrent forces Non-coplanar concurrent forces ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The time of flight of a projectile on downward inclined plane depends upon None of these Both (A) and (B) Angle of projection Angle of inclination of the plane None of these Both (A) and (B) Angle of projection Angle of inclination of the plane ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The center of gravity of a semi-circle lies at a distance of __________ from its base measured along the vertical radius. 3r/4π 3r/ 8 8r/3 4r/ 3π 3r/4π 3r/ 8 8r/3 4r/ 3π ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a solid sphere of mass ‘m’ and radius ‘r’ is mr²/2 2mr²/5 mr² 2mr²/3 mr²/2 2mr²/5 mr² 2mr²/3 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
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