MGVCL Exam Paper (30-07-2021 Shift 2) A wire pilot is generally economical for distances up to 75 km to 100 km 30 km to 60 km 10 km to 15 km 20 to 25 km 75 km to 100 km 30 km to 60 km 10 km to 15 km 20 to 25 km ANSWER EXPLANATION DOWNLOAD EXAMIANS APP A wire pilot is generally economical for distances up to 5 or 10 miles, beyond which a carrier-current pilot usually becomes more economical.
MGVCL Exam Paper (30-07-2021 Shift 2) What is the full form of the acronym 'AIDS' in diseases? Assert in Dander Syndrome Acquire in Deficiency Syndrome Amino Intersect Deficiency Syndrome Acquired Immune Deficiency Syndrome Assert in Dander Syndrome Acquire in Deficiency Syndrome Amino Intersect Deficiency Syndrome Acquired Immune Deficiency Syndrome ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Calculate the inductance per meter of a 50 Ω load cable that has an capacitance of 20 pF/m. 25 mH 50 nH 50 mH 25 nH 25 mH 50 nH 50 mH 25 nH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Characteristic impedance, Z = √(L/C)50 = √(L/20*10⁻¹²)L = (50*50)*(20*10⁻¹²)L = 50000*10⁻¹²L = 50 nH
MGVCL Exam Paper (30-07-2021 Shift 2) Recently, which country has withdrawn the 'Generalized System of Preferences' with India? United States of America Peru Pakistan Russia United States of America Peru Pakistan Russia ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is true regarding access lists applied to an interface? One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. You can apply only one access list on any interface You can apply two access lists to any interface One access list may be configured, per direction, for each layer 3 protocol configured on an interface You can place as many access lists as you want on any interface until you run out of memory. You can apply only one access list on any interface You can apply two access lists to any interface ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 1000 kVA ONAN cooled transformer has a load of 500 kVA throughout the day except for a period of 4 hours. What is the permissible overload for a duration of four hours. Assume the permissible load kVA as a fraction of rated kVA is 1.24. 2480 kVA 1240 kVA 930 kVA 620 kVA 2480 kVA 1240 kVA 930 kVA 620 kVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Permissible overload = Full load kVA*factor for permissible load= 1000*1.24= 1240 kVA
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