Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is [W (2 + f/G)]/A [W (2 + g/f)]/A [W (1 + f/ G)]/ A (1 – g/f)/A [W (2 + f/G)]/A [W (2 + g/f)]/A [W (1 + f/ G)]/ A (1 – g/f)/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures constant, depth of a cantilever of length of uniform strength loaded with Keeping breadth uniformly distributed load varies from zero at the free end and l) at the fixed end w l) at the fixed end 3w l at the fixed end 2w w l at the fixed end l) at the fixed end w l) at the fixed end 3w l at the fixed end 2w w l at the fixed end ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A spring of mean radius 40 mm contains 8 action coils of steel (N = 80000 N/mm²), 4 mm in diameter. The clearance between the coils being 1 mm when unloaded, the minimum compressive load to remove the clearance, is 25 N 40 N 35 N 30 N 25 N 40 N 35 N 30 N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In case of a simply supported rectangular beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is L/4 L/3 L/2 L/5 L/4 L/3 L/2 L/5 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = E/R = F/Y M/I = E/R = Y/F M/I = R/E = F/Y I/M = R/E = F/Y M/I = E/R = F/Y M/I = E/R = Y/F M/I = R/E = F/Y I/M = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be 8/5 2/3 5/8 3/2 8/5 2/3 5/8 3/2 ANSWER DOWNLOAD EXAMIANS APP
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