Fractions and Decimals
A has twice as much money as B. They play together and at the end of the first game B wins one-third of A's money from A, what fraction of the sum that B now has, must A win black in the second game,
Let A has Rs. 200 at the starting of game, then B has Rs. 100 at the starting of game.After the game, money left with A = 200 - 200/3 = Rs. 400/3 ∴ Total money with B = 100 + 200/3 = Rs. 500/3 Let the fraction of money lost by B = N Then, 500/3 - N x 500/3 = 400/3 + N x 500/3⇒ 500/3 - 400/3 = 500N/3 + 500N/3 ⇒ 100/3 = 1000N/3 ∴ N = (100/3) x (3/1000) = 1/10 so, the fraction of money lost is 1/10.
Let man's salary be Rs. NMoney spend on food =N/7Money spends on clothing = (N - N/7) x 1/2 = (6N/7) x (1/2) =3N/7Money spend on entertainment = (N - N/7 - 3N/7)/3 = (7N - 4N)/7 = N/7Now, money left =600⇒ N - N/7 - 3N/7 - N/7 = 600⇒ 7N - 5N/7 = 600⇒ N = 600 x 7/2 = Rs. 2100∴ Money spend on entertainment = 1/7 x 2100 = Rs. 300
Converting the given fractions into decimal form, we have,8/9 = 0.8818/23 = 0.7816/21 = 0.7614/17 = 0.82From the above, 0.88 is the largest.Corresponding fraction is 8/9.
EXAMIANS