RCC Structures Design A flat slab is supported On columns monolithically built with slab On beams and columns On columns On beams On columns monolithically built with slab On beams and columns On columns On beams ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Spacing of stirrups in a rectangular beam, is Increased at the centre of the beam Decreased towards the centre of the beam Increased at the ends Kept constant throughout the length Increased at the centre of the beam Decreased towards the centre of the beam Increased at the ends Kept constant throughout the length ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be. Parabolic with convexity downward Parabolic with convexity upward Straight below centroidal axis Straight above centroidal axis Parabolic with convexity downward Parabolic with convexity upward Straight below centroidal axis Straight above centroidal axis ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of the span to the overall depth does not exceed 10, the stiffness of the beam will ordinarily be satisfactory in case of a Continuous beam None of these Cantilever beam Simply supported beam Continuous beam None of these Cantilever beam Simply supported beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Long and short spans of a two way slab are ly and lx and load on the slab acting on strips parallel to lx and ly be wx and wy respectively. According to Rankine Grashoff theory (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)⁴ (wx/wy) = (ly/lx)² None of these (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)⁴ (wx/wy) = (ly/lx)² None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because All listed here Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress ANSWER DOWNLOAD EXAMIANS APP
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