RC Circuits A capacitor with 150Ω of capacitive reactance is across an ac source. The impedance, expressed in polar form, is Z = 150 angle – 90° Ω Z = 150 Z = 150 angle 180° Ω Z = 150 –90° Ω Z = 150 angle – 90° Ω Z = 150 Z = 150 angle 180° Ω Z = 150 –90° Ω ANSWER DOWNLOAD EXAMIANS APP
RC Circuits Point +4 on the complex plane is 4 units left of the origin on the real axis 4 units below the origin on the j axis 4 units right of the origin on the real axis 4 units above the origin on the j axis 4 units left of the origin on the real axis 4 units below the origin on the j axis 4 units right of the origin on the real axis 4 units above the origin on the j axis ANSWER DOWNLOAD EXAMIANS APP
RC Circuits The voltages in Problem 4 are measured at a certain frequency. To make the capacitor voltage greater than the resistor voltage, the frequency must be decreased must be increased has no effect is held constant must be decreased must be increased has no effect is held constant ANSWER DOWNLOAD EXAMIANS APP
RC Circuits When the frequency of the voltage applied to a series RC circuit is decreased, the impedance doubles decreases remains the same increases doubles decreases remains the same increases ANSWER DOWNLOAD EXAMIANS APP
RC Circuits A 47Ω resistor and a capacitor with a capacitive reactance of 120 are in series across an ac source. What is the circuit impedance, Z? 167Ω 129Ω 73Ω 12.9Ω 167Ω 129Ω 73Ω 12.9Ω ANSWER DOWNLOAD EXAMIANS APP
RC Circuits The complex number 40 angle 55° is equivalent to 22.94 + j32.76 55 + j55 40 + j40 45.88 + j65.52 22.94 + j32.76 55 + j55 40 + j40 45.88 + j65.52 ANSWER DOWNLOAD EXAMIANS APP
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