Applied Mechanics and Graphic Statics A ball which is thrown upwards, returns to the ground describing a parabolic path during its flight Horizontal component of velocity remains constant Kinetic energy of the ball remains constant Speed of the ball remains constant Vertical component of velocity remains constant Horizontal component of velocity remains constant Kinetic energy of the ball remains constant Speed of the ball remains constant Vertical component of velocity remains constant ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A uniform pyramid and a uniform prism of same height lie with their base on the surface. Which is more stable ? pyramid prism both equally stable None of these pyramid prism both equally stable None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The gravitational force makes a satellite go round the earth in a circular orbit, if it is projected with an initial velocity of 11.11 km/sec at a height of 37,400 km 8.04 km/sec at a height of 285 km All listed here 11.26 km/sec, the satellite escapes the pull of the earth 11.11 km/sec at a height of 37,400 km 8.04 km/sec at a height of 285 km All listed here 11.26 km/sec, the satellite escapes the pull of the earth ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In a lifting machine a weight of 5 kN is lifted through 200 mm by an effort of 0.1 kN moving through 15 m. The mechanical advantage and velocity ratio of the machine are respectively 50 and 75 75 and 75 75 and 50 50 and 50 50 and 75 75 and 75 75 and 50 50 and 50 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = √(2gh) v = 1/√(2gh) v = 2gh² v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² v = 2gh ANSWER DOWNLOAD EXAMIANS APP
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