Stoichiometry 80 kg of Na₂SO₄ (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na₂SO₄ .10H₂O crystals separate out. The weight fraction of Na₂SO₄ in the remaining solution is 0.18 1 0.24 0.18 1 0.24 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Hess's law of constant heat summation is based on conservation of mass. It deals with Reaction rate Changes in heat of reaction Equilibrium constant None of these Reaction rate Changes in heat of reaction Equilibrium constant None of these ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The vapour pressure of a solution (made by dissolving a solute in a solvent) is __________ that of the pure solvent. Equal to Less than Either more or less; depends on the solvent More than Equal to Less than Either more or less; depends on the solvent More than ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Colligative properties of a dilute solution are those, which depend entirely upon the Number of solute molecules contained in a given volume of the solvent Constitution of the solute None of these Chemical composition of the solute Number of solute molecules contained in a given volume of the solvent Constitution of the solute None of these Chemical composition of the solute ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Na₂SO₄. 10H₂O crystals are formed by cooling 100 Kg of 30% by weight aqueous solution of Na₂SO₄. The final concentration of the solute in the solution is 10%. The weight of crystals is 58.65 20 32.2 45.35 58.65 20 32.2 45.35 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Kopp's rule is concerned with the calculation of Surface tension Viscosity Heat capacity Thermal conductivity Surface tension Viscosity Heat capacity Thermal conductivity ANSWER DOWNLOAD EXAMIANS APP